Question

For what value(s) of 'k' the quadratic equation (k - 2)x² + kx - 2x + 1 = 0 has equal roots.​

Answer 1

Step-by-step explanation:

Given equation is

2x^(2)-kx+k=0

<br> On comparing with

ax^(2)+bx+c=0

we get <br>

a=2,b=-k

and

c=k

<br> For equal roots, the discriminant must be zero.<br> i.e.,

D=b^(2)-4ac=0

<br>

= (-k)^(2)-4(2)k=0

<br>

implies k^(2)-8k=0

<br>

implies k(k-8)=0

<br>

:. k=0,8

<br> Hence the required values of

k

are 0 and 8.

please mark me as brainliest