Question

For what value(s) of n, the equation (n+3)x2-(5-n)x+1=0 has coincident roots?​

Answer 1

Answer:

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Answer 2

Answer:

Option a

Step-by-step explanation:

Correct option is

A

1,13

For coincident roots, D=0

Now, [−(5−k)]

2

−4×(k+3)×1=0

⇒25+k

2

−10k−4k−12=0

⇒k

2

−14k+13=0

⇒(k−13)(k−1)=0

∴k=13,1