For what value (s) of 'p' quadratic equation px? + 6x + 9 = 0 has no real
roots ?
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Step-by-step explanation:
a=1 ,b=6, c=9
b-4ac
(6)- 4×1×9
36-36
0
D=0
x= -6+0/2×1 x=-6-0/2×1
x=-6/2 x=-6/2
x=-3 x=-3
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