For what values of a and b does the following pair of equations have an infinite numbers of solutions. 2x+3y=7, a(x+y)-b(x-y)=3a+b-2
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2x +3y =7
Subtract 7 both side we get
2x + 3y - 7 = 0
(a – b) x +(a +b) y =3a +b –2
Subtract 3a + b -2 both side we get
(a – b) x +(a +b) y - (3a + b – 2) = 0
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Hence answer is a = 5 and b = 1
Subtract 7 both side we get
2x + 3y - 7 = 0
(a – b) x +(a +b) y =3a +b –2
Subtract 3a + b -2 both side we get
(a – b) x +(a +b) y - (3a + b – 2) = 0
Compare with



Hence answer is a = 5 and b = 1
Answered by
2
answer is a 5 and b1
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