Question

For what values of a are 3a + 24, 4a + 29, and 6a + 31 sequential members of an
arithmetic progression?

Answer 1

Answer:

$if \: it \: is \: in \: ap \\ then \: b = \frac{a + c}{2} \\ b = 4a + 29 \\ a = 3a + 24 \\ c =6 a + 31$