Question

for what values of a are 3a+24,4a+29 and 6a+31 sequential members of an arithmetic progression?

Answer 1

Answer:

hey here u go

Step-by-step explanation:

if it is in ap

then b=a+c/2

b= 4a+29

a= 3a+29

c= 6a+29

hope it helps u : )

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