Question

For what values of 'a' is 2x3+ax2+11x+a+3 is exactly divisible by (2x-1)

Answer 1

Hey Mate,
Here is your Answer.

Since 2x-1 divides, then 1/2 must be a solution. 

We can solve by inserting 1/2 for x: 
2(1/8) + a(1/4) + 11/2 + a + 3 = 0 
1/4 + a/4 + 11/2 + a + 3 = 0 
1/4 + a/4 + 22/4 + 4a/4 + 12/4 = 0 
(5a + 35)/4 = 0 
5a + 35 = 0 
a = -7

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