Math, asked by hamsacp57, 2 months ago

For what values of 'a'the quadratic equation 30ax saqure -6x + 1 =0 has no real roots​

Answers

Answered by ajb7899
1

Step-by-step explanation:

No real root when D =

 {b}^{2}  - 4ac  <  0

(-6)^2 - 4x 30a x 1 < 0

36 - 120a < 0

-120 a < -36

a > 36/120

a > 3/10

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