For what values of ‘a’ the quadratic equation 9x2 – 3ax + 1 = 0 has equal roots ?
Answers
Answered by
7
Answer:
a quadratic equation will have same roots when its discriminant is zero
so D=0
√(b²-4ac)=0
here b=3a
a =9
c=1
9a²=4×9×1
a²= 4(9 cancells out)
a=±2
Answered by
3
Answer:
Step-by-step explanation:
a=9 b= -3a c=1
b^2-4ac=0
(-3a)^2- 4(9)(1)
9a-36
9a=36
a=36/9
a=4
-b+or- root b^2-4ac /2a
-(-3a)+or- root 4/ 18
3a+2/18 or 3a-2/18
a+1/3 or a-1/3
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