Question

for what values of K are the. 8, 1, 3,- 2 k and K, - 5 are collinear​

Answer 1

Answer:

k=2,11/2

Step-by-step explanation:

Since the points are collinear,area of triangle =0

1/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]=0

=8(-2k+5)+3(-5-1)+k(1+2k)=0*2/1

                                           =0

=-16k+40-18+k+2k²=0

=2k²-15k+22=0

=2k²-4k-11k+22=0

=2k(k-2)-11(k-2)=0

(k-2)(2k-11)=0

∴ k=2,11/2