Question

For what values of k are the points (8,1) , (3,-2k) and (k,-5) collinear ?

Answer 1

Answer:

Let A(x1=8,y1=1),B(x2=3,y2=−2k) & C(x3=k,y3=−5)

be the given point

The given points are collinear if

x1(y2−y3)+x2(y3−y1)+x3(y1−y2)=0

on puting values we get

8(−2k+5)+3(−5−1)+k(1+2k)=0

−16k+40−18+k+2k2=0

2x2−15x+22=0

2k2−4k−11k+22=0

2k(k−2)−11(k−2)=0

(2k−11)(k−2)=0

k=2

Answer 2

Answer:

Step-by-step explanation: