For what values of k are the roots of the quadratic equation kx(x-4 underroot5) +20=0
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Answer:
The given equation 3x
2
+2kx+27=0
Here, a=3,b=2k,c=27
It is given that roots are real and equal.
∴ b
2
−4ac=0
⇒ (2k)
2
−4(3)(27)=0
⇒ 4k
2
−324=0
⇒ 4k
2
=324
⇒ k
2
=81
∴ k=±9
Step-by-step explanation:
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