Question

For what values of k, do the pair of equations kx + y = k 2 and x + ky = 1 has unique solution?

Answer 1

a1 / a2 = b1 / b2 not = c1 / c2

therefor we get a1 / a2 = b1 / b2 ; k = 1 / k

k[sq] = 1

k = 1

for unique solutions

a1 / a2 not = b1 / b2

k / 1 not = 1 / k

k[sq] not = 1

k not = 1.

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