For what values of k, do the pair of equations kx + y = k 2 and x + ky = 1 has unique solution?
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a1 / a2 = b1 / b2 not = c1 / c2
therefor we get a1 / a2 = b1 / b2 ; k = 1 / k
k[sq] = 1
k = 1
for unique solutions
a1 / a2 not = b1 / b2
k / 1 not = 1 / k
k[sq] not = 1
k not = 1.
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