Question

For what values of k does the pair of linear equations in two variables 4x+ky+5=0 and

2x+2y+2=0 has unique solution.

(a) K=4 (b)k#4 (c) k=1 (d) none of these​

Answer 1

Answer:

b) k is not equal to 4

Step-by-step explanation:

4x+sky + 8 = 0

2x +2y+ 2 =0

a1x + b1y - c1 = 0

a2x + b2y - C2 = 0

a1 = 4 , b1 = k , c1 = 8

a2 =2, b2=2 , c2= 2

so unique solution

a1/a2 not equal to b1/b2

4/2 not equal to k/2

therefore k is not equal to 4

hope u will get it...