Question

for what values of k does the quadratic equation 4x2-12x-k=0 have no real roots.​

Answer 1

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Answer 2

Answer:

Hence, the value of k is any integer smaller than -9. k < -9

Step-by-step explanation:

Given,

P(x) = 4x^2 - 12x - k, has no real roots.

Here, a = 4 , b = -12 , c = -k

We know that,

D < 0 , then the roots are imaginary,

Thus, here D < 0

Also, D = b^2 - 4ac

=> (-12)^2 - 4 × 4 × -k < 0

=> 144 + 16k < 0

=> 16k < -144

=> k < -144/16

=> k < -9

Hence, the value of k is any integer smaller than -9. k < -9