Question

For what values of k if x = 2, y=3 is a solution of (k+1)x-2(2k+3)y-1=0

Answer 1

Answer:

Step-by-step explanation:

(k+1)2-6(2k+3)-1=0

2k+2-12k-18-1=0

-10k=19

k=-1.9