Question

For what values of k, roots of 2x^2+4x+128=0, imaginary(not real)

Answer 1

Step-by-step explanation:

2x

2

−Kx+x+8=0

2x

2

+(1−K)x+8=0

For real and equal roots

D=0

(1−K)

2

−4.2.8=0

K

2

−2K−63=0

(K−9)(K+7)=0

K=9 or −7