Question

For what values of k, the equation 9x² + 6kx + 4 = 0 has equal roots?​

Answer 1

Given that

• 9x² + 6kx + 4 = 0

To Find

• Value Of K

→9x² + 6kx + 4 = 0

a=9 , b=6k , c=4 and d=0

Therefore b²-4ac=0

$\\{\sf → (6k)²-4×9×4=0 }$

$\\{\sf → 36k²-144=0 }$

Adding Both Sides By 144

$\\{\sf → 36k²-144+144=0+144 }$

${\sf → 36k²=144 }$

Diving both sides by 36

${\sf →36k²/36=144/36 }$

${\sf →k²=4 }$

${\sf →k=\sqrt{4} }$

$\pink{\underline{\boxed{{\bf ~~~~~ k=2 }}}}$