Question

For what values of k, the equation kx2 - 6x - 2 =0 has real roots?
whoever will give right answer will get a brainliest​

Answer 1

Answer:

k= -9/2

Step-by-step explanation:

kx^2 - 6x - 2 = 0

for equal roots

b^2 - 4ac=0

(-6)^2 - 4(k)(-2)=0

36 - (-8k) = 0

36 + 8k =0

8k = -36

k = -36/8

k= -9/2