Question

For what values of k the following linear equation have no solution :-3x-y=5or 6x-2y=k

Answer 1

Answer:

Given that the equations are,

3x-y-5=0, 6x-2y-k=0

Since they has no solution

They are parallel.....

The condition is,

a1/a2=b1/b2≠c1/c2

3/6=1/2≠5/k

5/k≠1/2

K≠10

So the value of k is not equal to the 10....

Step-by-step explanation:

Hope it helps you frnd......

Answer 2

✳ Given ✳

The following 2 equations have no solution :-

• 3x - y = 5        . . . (i)
• 6x - 2y = k      . . . (ii)

a₁ = 3, a₂ = 6, b₁ = -1, b₂ = -2, c₁ = -5, c₂ = k

✳ To Find ✳

➩ The value of k for which the given equations have no solution.

✳ Solution ✳

We know, for no solutions,

$\boxed{\sf{\color{magenta}{\frac{a_1}{a_2}=\frac{b_1}{b_2} \neq \frac{c_1}{c_2} }}}$

Putting the values :-

$\displaystyle{\sf{\longrightarrow \frac{3}{6}=\frac{-1}{-2} \neq \frac{-5}{-k} }}\\\\\displaystyle{\sf{\longrightarrow \frac{1}{2}=\frac{1}{2} \neq \frac{5}{k} }}\\\\\displaystyle{\sf{\longrightarrow \frac{1}{2} \neq \frac{5}{k} }}\\\\\boxed{\displaystyle{\color{lime}{\sf{\longrightarrow k \neq 10 }}}}$

Hence, the value of k is any integer except 10.