For what values of k , the following system of equations has infinitely many solutions: k x + 5 y – ( k – 5) = 0 20 x + k y – k = 0
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Answer:
the value of k is 10 in both the equations
Step-by-step explanation:
here for infinite solutions a1/a2 = b1/b2 = c1/c2
here k/20 = 5/k = k-5/k
I) k/20 = 5/k
k×k = 20×5
{k}^{2} = 100k
2
=100
k=√100
thus k= 10
ii) k/20 = (k-5)/k
k×k = 20×(k-5)
{k}^{2} = 20k - 100k
2
=20k−100
{k}^{2} - 20k = - 100k
2
−20k=−100
k(k - 20) = - 100k(k−20)=−100
k= 10
k - 20 = 100 \div 10k−20=100÷10
k - 20 = - 10k−20=−10
\begin{gathered}k = - 10 + 20 \\ k = 10\end{gathered}
k=−10+20
k=10
therefore the value of k is 10 in both the equations
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