Question

for what values of k the pair of linear equations 2x+y+3=0 and 6x+ky+9=0,has infinitely many solutions​

Answer 1

Answer:

k=3

Step-by-step explanation:

For Infinity many solution

a1/a2 = b1/b2 =c1/c2

2/6 = 1/k = 3/9

=2k= 6

= k=6/2

K = 3

Answer 2

Answer:

for infinitely many solution lines need to be coincident that is a1/a2= b1/ b2= c1/c2

Step-by-step explanation:

a1/a2=2/6

b1/b2= 1/k

c1/c2= 3/9

hence a1/a2=b1/b2

2/6=1/k

2k=6

k=6/2

k=3