Question

For what values of k the points (0,0),(1,3),(2,4) and (k,3) are concyclic

Answer 1

Answer: k=-1,5

Brainliest solution

Step-by-step explanation:

A(0,0),B(1,3),C(2,4),D(k,3)

Concyclic means AB=CD

√(3-0)^2+(1-0)^2=√(k-2)^2+(3-4)^2

√9+1=√(k-2)^2+1

10=(k-2)^2+1

(k-2)^2=9

k-2=3,k-2=-3

k=5,k=-1