Question

For what values of k the quadratic equation x 2 - kx + 4 = 0 has equal roots?

Answer 1

b^2-4ac =∆(D)
=(-k)^2-4(1)(4)=0
k^2-16=0
k = 4
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Answer 2

SOLUTION :  

Given : x² - kx + 4 = 0  has equall roots.

On comparing the given equation with ax² + bx + c = 0  

Here, a = 1 , b = - k  , c = 4

D(discriminant) = b² – 4ac

D = (- k)² - 4 × 1 × 4

D = k² - 16  

D = 0 (Given : equal roots )

k² - 16 = 0

k² = 16

k = √16  

k = ± 4

Hence, the value of k is ± 4 .

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