For what values of k the quadratic equation x 2 - kx + 4 = 0 has equal roots?
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Answered by
6
b^2-4ac =∆(D)
=(-k)^2-4(1)(4)=0
k^2-16=0
k = 4
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=(-k)^2-4(1)(4)=0
k^2-16=0
k = 4
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Answered by
9
SOLUTION :
Given : x² - kx + 4 = 0 has equall roots.
On comparing the given equation with ax² + bx + c = 0
Here, a = 1 , b = - k , c = 4
D(discriminant) = b² – 4ac
D = (- k)² - 4 × 1 × 4
D = k² - 16
D = 0 (Given : equal roots )
k² - 16 = 0
k² = 16
k = √16
k = ± 4
Hence, the value of k is ± 4 .
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