For what values of K, the roots of the equation 3x ^ 2 - 10x + K = 0 are real?
Answers
Answered by
5
Answer:
k=25/3
Step-by-step explanation:
3x^2-10k+k=0
comparing with ax^2+bx+c=0
a=3, b= -10, c=k
but root r real
b^2-4ac= 0
(-10)^2-( 4×3×k)= 0
100 -12k= 0
12k= 100
k=100/12
k= 25/3
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