Math, asked by khushboomaharana06, 1 day ago

For what values of K, the roots of the equation 3x ^ 2 - 10x + K = 0 are real?​

Answers

Answered by popatkhot1977
5

Answer:

k=25/3

Step-by-step explanation:

3x^2-10k+k=0

comparing with ax^2+bx+c=0

a=3, b= -10, c=k

but root r real

b^2-4ac= 0

(-10)^2-( 4×3×k)= 0

100 -12k= 0

12k= 100

k=100/12

k= 25/3

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