Question

For what values of k, the roots of the equation x square + 4x + k= 0 are real​

Answer 1

${ \huge{ \underline{ \underline{ \sf{ \green{GivEn : }}}}}}$

• An equation ____ x² + 4x + k = 0

${ \huge{ \underline{ \underline{ \sf{ \green{To \: find :}}}}}}$

• Value of k

Formula to be used :-

• Discriminant = b² - 4ac

${ \huge{ \underline{ \underline{ \sf{ \green{SoluTion : }}}}}}$

Given,

Equation _____x² + 4x + k = 0

where,

a = 1

b = 4

c = k

___________________________________________________

We know that,

if the equation has two real and equal roots then , Discriminant will be = 0

Now,

⟶ b² - 4ac = 0

⟶ 4² - 4 × 1 × k = 0

⟶ 16 - 4k = 0

⟶ -4k = -16

⟶ 4k = 16

⟶ k = 16/4

⟶ k = 4

Hence, value of k is = 4