Question

For what values of k, the roots of the equation x2 + 4x + k = 0 are real?

Answer 1

solution

$\sqrt{4 {}^{2} - 4(1)(k) } = 0 \\ = > 16 - 4k = 0 \\ = > k = \frac{16}{4} \\ = > k = 4$

Answer 2

Answer:

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