For what values of k, the roots of the equation x2 + 4x + k = 0 are
real and equal?
Answers
Answered by
0
Answer:
Real = x2 + 4x + k
Equal = 0
Answered by
1
Answer:
K = 4
Explanation:
let ax^2 +bx + c be quadratic equation
let x be the roots of given quadratic equation
Sum of roots(zeroes) = -b/a = -4/1 = -4
=> x + x = -4
=> 2x = -4 => x = -2
prodcts of roots(zeroes) = c/a = k/1 = k
=> x^2 = k
=> (-2)^2 = k
=> k = 4
Hope it helps
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