for what values of k, the roots of the equation x²+4x+k =0 are real
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Answer:
Step-by-step explanation:
Given equation :- x²+4x+k =0
If the roots are real then ,
b² - 4ac = 0
4² - 4×1×k = 0
16 - 4k = 0
- 4k = -16
4k = 16
k = 16/4 = 4
∴ The value of k is 4
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