Question

for what values of k will the following pair of equations have have no solutions 4x+ky=8, 2x+2y+2=0​

Answer 1

Answer:

HOW TO SOLVE?

For no solution,

$\frac{a1}{a2} = \frac{b1}{b2}$

So, the result will come as,

$\frac{4}{2} = \frac{k}{2} \\ 8 = 2k \\ k = \frac{8}{2} \\ k = 4$

These pair of equations should have k's value 4 to have no solution.

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