Question

For what values of k will the following pair of linear equation have no solution Kx+3y-(k-3)=0 12x+ky-k=0

Answer 1

Step-by-step explanation:

kx+3y-(k-3) =0

or, kx+3y-k+3=0

or, k(x-1) +3(y+3)=0

or, k=-3(y+3)/(x-1)

12x+ky-k=0

or, 12x+k(y-1)=0

or, k=-12x/(y-1)