CBSE BOARD X, asked by jaydevsahu8798, 1 year ago

For what values of k will the following pair of linear equations have infinitely many solutions? Kx + 3y - (k-3) =0

Answers

Answered by Rajput0111
3

Hey Mate Heres the ans //;

Condition for infinity solutions ;

a1/a2=b1/b2=c1/c2

Apply it u will get the answer

Answered by tanmoyvestige
6

Comparing it with ax2 +bc +c=0 we get,

a=k, b= 3 and c=k-3

∆ = b2- 4ac

= (3)2- 4×3×k×3

= 9 - 36k

k = 36 - 9

k. = 27

And

Comparing it with ax2 +bc + c = 0 We get,

a = 12, b= k and c = -k

∆ = b2 - 4ac

= (k)2 - 4× 12×k

= k - 48k

k = 48k

k2 = 48

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