For what values of ‘k’ will the pair of linear equation have an infinitely number of solutions 3x + 2y = 1 and (2k + 1)x + (k+2)y = k – 2
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Answer:
k=7
Step-by-step explanation:
given
3x + 2y = 1 and (2k + 1)x + (k+2)y = k – 2
any two equation have to equal ratio
so 3/(2k+1)=1/(k-2)
after solve this we get k=7
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