Math, asked by aditi6180, 1 year ago

For what values of k , will the system of equations x + 2y = 5 3x + ky - 15 = 0 has a no solution

Answers

Answered by broke
13
Hey

Here is ur answer

The equations are x+2y=5
And 3x+ky-15=0

On comparing with the general form of equation a1x+b1y+c1=0 and a2x+ b2y+c2=0

We get
a1=1 b1=2 and c1= -5
And a2=3. b2=k c2=-15

Condition for no solution is
a1/a2= b1/b2 not equal to c1/c2
Now
a1/a2=b1/b2
1/3=2/k
k= 2*3= 6
K=6

And
b1/b2not equal to c1/c2
2/k not equal to -5/-15
2/k not equal to 1/3
k not equal to 6

Therefore the answer is k=6

Hope it helps you
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