For what values of m, 2x³+mx²+11x+3is exactly divisible by 2x-1
Answers
Answered by
6
2×(1/2)³+m(1/2)²+11(1/2)+3= 0
=2/8+m/4+11/2+3 = 0
now find the balue of m
Answered by
18
Answer:
Step-by-step explanation:
if given polynomial is divisible by 2x-1, then
2x-1 is a factor of 2x^3+mx^2+11x+3
therefore, putting x=1/2 in the given polynomial gives remainder zero
hence, 2(1/2)^3 + m(1/2)^2 + 11(1/2) + 3 =0
solving above eq. we get
2*(1/8) + m*(1/4) + (11/2) + 3 = 0
1/4 + m/4 + 22/4 + 12/4 = 0
1+m+22+12 = 0
m = -43
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