for what values of M the polynomial x cube - 2mx square + 16 is divisible by (X + 2) ?
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hey the answer is ....
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ShuchiRecites:
Hi sis, mistakes in solution of yours
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✪ Answer : 1
✪ Step-by-step explanation :
p(x) = x³ - 2mx² + 16
Where divisor is ( x + 2 ) and we get remainder i.e., final value of p(x) as 0.
So value of x here is - 2
p(-2) = -2³ - 2m(-2)² + 16
0 = - 8 - 8m + 16
0 = - 8 + 16 - 8m
0 = + 8 - 8m
+ 8m = + 8
m = 8/8
⇒m = 1
Final value of m is 1.
✪ Step-by-step explanation :
p(x) = x³ - 2mx² + 16
Where divisor is ( x + 2 ) and we get remainder i.e., final value of p(x) as 0.
So value of x here is - 2
p(-2) = -2³ - 2m(-2)² + 16
0 = - 8 - 8m + 16
0 = - 8 + 16 - 8m
0 = + 8 - 8m
+ 8m = + 8
m = 8/8
⇒m = 1
Final value of m is 1.
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