Question

for what values of 'm' will the equation 2mx²-2(1+2m)x+(3+2m)=0 have a real but distinct roots ? when will the root be equal

Answer 1

Hope this helps......

Answer 2

Answer:

m=1/2

Step-by-step explanation:

According to bx^{2} -4ac

=[-2(1+2m)]^{2} -4*2m*(3+2m)=0

=4(1+2m{2} )-8m(3+2m)=0

=4(1+4m+4m^{2} )-24m-16m^{2} =0

=4-8m=0

=1-2m=0

m=1/2