for what values of m will the equation (m+1)x^2+2(m+3)x+(m+8)=0 has equal roots
Answers
Answered by
25
For equal roots, we must have D=0
or, b^2 - 4ac = 0 (b square minus 4ac okk)
or, {2(m+3)}^2-4(m+1)(m+8)=0
or, (2m+6)^2-4(m^2+9m+8)=0
or, (4m^2+24m+36)-4m^2-36m-32=0
or, -12m+4 =0
or, 12m = 4
or, m = 4/12
Hence, the answer is m=1/3. Hope it helped and plss mark brainliest.
or, b^2 - 4ac = 0 (b square minus 4ac okk)
or, {2(m+3)}^2-4(m+1)(m+8)=0
or, (2m+6)^2-4(m^2+9m+8)=0
or, (4m^2+24m+36)-4m^2-36m-32=0
or, -12m+4 =0
or, 12m = 4
or, m = 4/12
Hence, the answer is m=1/3. Hope it helped and plss mark brainliest.
Anonymous:
will u mark my answer brainliest???plss
Similar questions