For what values of m will the equation x2+mx-(m 2+m-32)=0 has equal roots
Answers
I guess when you say that a quadratic equation has equal values, you actually mean the equation having identical roots. I attempt my answer with this understanding but just in case I am mistaken, I am sorry.
A quadratic equation of the form ax^2+bx+c=0 has identical roots when its discriminant: b2−4ac equals 0 .
Upon comparing your equation with the standard form, a=1,b=m and c=−(m2+3m−32)
So, we have that, for the equation x2+mx−(m^2+3m−32) to have identical roots, m must satisfy the equation m2+4(1)(m2+3m−32)=0
⇒m^2+4m2+12m−128=0
⇒5m2+12m−128=0
This itself is a quadratic equation in m , and by the theory of quadratic equations, the roots of this equation are
−12±122+4×5×128−−−−−−−−−−−−−−√2×5
=−12±144+2560−−−−−−−−−√10=−12±2704−−−−√10
=−12±5210
So, the possible values of m are −12−5210 and −12+5210
or, −6410 and 4010
or, −32/5 and 4