Question

for what values of n, are the nth terms of two A. Ps : 63,65,67,....... and 3,10,17,....... equal
please don't write anything useless if you don't know the answer...... ​

Answer 1

Answer:

63,65,67.......

a=63,d=2

nth term =a+(n+1)d

=63+(n+1)2

=61+2n

(b)

3,10,17....

a=3,d=7

nth term =a+(n−1)d

=3+(n−1)7

=−4+7n

Now nth terms of 2 ap’s as equal

So 61+2n=7n−4

⇒5n=65

⇒n=13

13th term of A.p.s are equal

Step-by-step explanation:

hope it is helpful

Answer 2

Answer:

The given Question is solved in the uploaded photos.