Question

For what values of n nth term of the series 3, 10, 17...and 63, 65, 67..are equal.

Answer 1

First A.P. 3,10,17,....
a=first term=3
d =common difference=7
Second A.P. 63,65,67.....
A=first term=63
D=common difference=2
For equal nth term
Tnth=Tnth
a+(n-1)d=A+(n-1)D
=>3+(n-1)7=63+(n-1)2
=>7n-4=2n+61
=>5n=65
=>n=13
At n=13
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Answer 2

Answer:

n = 13

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