For what values of p. -4 is a zeroes of polynomial x3-2x-(7p+3)
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Answered by
3
X^3-2x-(7p+3)=0
= x^3 - 2x - 7p - 3 =0
= 4^3 - 2*4-7p -3=0
= 12 - 8 - 7p - 3 = 0
= 1 - 7p =. 0
= p = 1/7
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Potenz:
4^3 = 64....
-4... Why don't you edit the answer :)
Answered by
2
Substitute the value of x in the equation;p(x) = p(-4) or any zeroes of the polynomial and equate it.
Solve it and you will get the answer!
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