Question

For what values of p. -4 is a zeroes of polynomial x3-2x-(7p+3)

Answer 1

X^3-2x-(7p+3)=0

= x^3 - 2x - 7p - 3 =0

= 4^3 - 2*4-7p -3=0

= 12 - 8 - 7p - 3 = 0

= 1 - 7p =. 0

= p = 1/7

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Answer 2

Substitute the value of x in the equation;p(x) = p(-4) or any zeroes of the polynomial and equate it.

Solve it and you will get the answer!