Math, asked by abhishek0078640, 9 months ago

For what values of p and q, the expression,
x⁴ - 14x³ + 71x² + px +q is a perfect square?​

Answers

Answered by BhArgavRaMram
0

Answer:

p=-546, q=1521;;;

Step-by-step explanation:

let me assume that the square root of the equation is a quadratic equation

x^2+ax+b=0;(x^2 coefficient is 1 cuz we can infer from the equation in the question)

so (x^2+ax+b)^2=x^4-14^3+71x^2+px+q

compare the coefficients after expanding the equation

do the math you will find a=-7 b=39

comparsion gives p=2ab q=b^2

so p=-546 q=1521

this m8 help:)

Similar questions