Math, asked by krishvaidya44, 9 months ago

For what values of ‘p’ does the pair of equation given below has unique

solution?

4x + py + 8=0

2x + 2y + 2=0​

Answers

Answered by MausamMagar
27

Answer:

Your equations are:

4x + py + 8=0    .......(1)                

and     2x + 2y + 2=0​                                                  

2(x+y+1) = 0

(x+y+1) =0/2

x+y+1 = 0      ........(2)

from (1)  and (2)

a1 = 4 , a2 = p,  a3 = 8

b1 = 1,  b2 = 1,   b3 = 1

for unique solution,

a1/a2 \neq b1/b2 = c1/c2

4/1 \neq p/1 = 8/1

4/1 \neq p/1     &   p/1 = 8/1

4 \neqp        &  p = 1    ans.

I hope this helped you.

pls mark me as a brainiest if it helped you.

Similar questions