Question

For what values of p does the pair of equations 4x + p y +8 =0 and 2x +2y +2 =0 has unique solution?

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Answer 1

Answer:

to have unique soln a1/a2≠b1/b2

4/2≠p/2,,,,,,p≠4

p can take any value except 4

Answer 2

Answer:4

Explanation:

Given equation:-

4x+py+8=0

a1​=4,b1​=p,c1​=8

2x+2y+2=0

a2​=2,b2​=2,c2​=2

Since the given pair of equation hs unique solution.

Therefore,

a2​a1​​=b2​b1​​

24​=2p​

⇒p=4

Hence the given pair of equation has unique solution for all values of p except 4.