Question

for what values of p will the sum of squares of the roots of x^2-px-1+p=0 be minimum THE ANSWER IS ONE PLEASE EXPLAIN ILL MARK YOU AS BRAINLIEST

Answer 1

Answer:

p=2

Step-by-step explanation:

in this equation,x^2-px-1+p=0

a=  1

b=  -p

c=  p-1

now sumof squares of zeros is minimum=0

[because it can never be negative]

thus,α²+β²=0

or

[α-β]²-2αβ=0

[α+β]²=2αβ

-b/a=2c/a

-b=2c

p=2[p-1]

p=2p-2

p=2

regards......