Math, asked by Matatagi8512, 1 year ago

For what values of the following system of linear equation have no solution
(a) 3x+y=1
(b) (2k-1)x+(k-1)y=2k+1

Answers

Answered by Anonymous
4
Hi Mate!!!

Conditions for no solutions is

{ 3 / ( 2k - 1 ) } = { 1 / ( k - 1 ) }


=>


3 ( k -1 ) = ( 2k - 1 )

3k - 3 = 2k - 1

k = 2


So, the value of k is 2


Have a nice time.


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