Question

For what values of x and y are the numbers 3+ix2y and x2



+ y + 4i conjugate complexes?

Answer 1

Ans. y = (-1) and x^2 = 4 or x=(+-4) ... solution is in the attached pic ... :)

Answer 2

Thank you for asking this question, here is your answer:

Let z1=−3+ix2y and z2=x2+y+4i

z1=−3−ix2y  and z2¯¯¯¯¯=x2+y−4i

z1=z2 and z2=z1

−3−ix2y=x2+y+4i  and x2+y−4i=−3+ix2y

x2+y=−3 and x2y=−4

−4/y +y=−3

y2+3y−4=0

y=−4 or y=1

wheny=−4,x=±1

wheny=1,x2=−4 (this is not possible)

(x,y)=(±1,−4)

If there is any confusion please leave a comment below.