Question

For what valve(s) of k does quadratic equation 25x^2-10kx+49 have equal roots

Answer 1

D=b2-4ac
D=(-10k)2-4(49)(25)
D=100k2-4900
D=100k2=4900
k2=4900/100
k2=49
k=√49
k=7
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Answer 2

d=b²-4ac
here d=0(given, for equal roots)
so, a=25 , b=-10k , c=49
and,
0=(-10k)²-4(25)(49)
0=100k²-4900
0=(10)(10k²-490)
so, k= 0
or,
10k²-490=0
10k²=490
k²=490/10
k²=49
k=7