Question

for whatvalue of k is -3 a zero of the polynomial x2+11x+k

Answer 1

Answer:

(-3)^2 +11 (-3) +k =0

9-33+k =0

-24 + k =0

k = 24

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Answer 2

Given polynomial is

${x}^{2} + 11x + k$

and also given that zero is (-3)

By substituting the value in x terms , we get

${-3}^{2} + (11 \times -3) + k = 0$

$9 - 33 + k = 0$

$-24 + k = 0$

$k = 24$

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